 This puzzle was basically reading a list of numbers, performing some basic arithmetic, and summing the results. For part two, there’s a twist in that I’ll need to do that same math on the results, and add then as long as they are greater than 0.

## Challenge

The puzzle can be found here. I’m given a text file with many lines, each with a single int. For part 1, I’m to read each line as a weight, and calculate the amount of fuel necessary which is proprotional to the weight, fuel = max(floor(weight / 3) - 2, 0). I’m asked to sum this fuel number to get a total fuel required. For part 2, I need to take into account the weight of the fuel, and bring fuel for that.

## Solution

### Part 1

For part 1, after reading in the file and converting each line to an int, I can use one of my favorite features in Python, List Comprehensions. This allows me to perform some action on each item in the array, resulting in a new array, which I can them sum.

To solve part 1, my code was simply:

#!/usr/bin/env python3

import sys

with open(sys.argv, 'r') as f:
weights = [int(l) for l in f.readlines()]

total_fuel = sum([(w//3)-2 for w in weights])
print(f"Part 1: {total_fuel}")


### Part 2

In part 2, I need to take into account the weight of the fuel, and calculate it stepwise and add it in as long as it’s positive. I started to think about a recursive function, but a loop worked just find and lead to simpler code.

At first, I did make one mistake. See if you can spot it:

total_fuel_plus = 0

for w in weights:
while w > 0:
w = (w//3) - 2
total_fuel_plus += w

print(f"Part 2: {total_fuel_plus}")


My result was coming in too low. That’s because I was adding in a negative before breaking. For example, if the w were 40, I would get 11, then 1, and then -2, which sum to 10. But I really only want to add the positives.

I updated the code to check that w was greater than 0 before adding it to the total, and it returns the correct answer:

total_fuel_plus = 0

for w in weights:
w = (w//3) - 2
while w > 0:
total_fuel_plus += w
w = (w//3) - 2

print(f"Part 2: {total_fuel_plus}")


## Final Code

#!/usr/bin/env python3

import itertools
import sys

with open(sys.argv, 'r') as f:
weights = [int(l) for l in f.readlines()]

total_fuel = sum([(w//3)-2 for w in weights])
print(f"Part 1: {total_fuel}")

total_fuel_plus = 0

for w in weights:
w = (w//3) - 2
while w > 0:
total_fuel_plus += w
w = (w//3) - 2

print(f"Part 2: {total_fuel_plus}")