 Today I’m tasked with building on the simple computer I built in day 2. I’ll add new instructions for input / output and comparisons / branching. I’ll also get parameter modes, so in addition to reading values from other positions, I can now handle constants (known in computer architecture as immediates).

## Challenge

The puzzle can be found here. I’ll start with the computer from day 2, and in part one I’ll add the concept of input and output. The user is prompted for input using opcode 3 (which is provided for each part), and then a series of diagnostic tests are run. For each of them, the result is printed using opcode 4. Each of these opcodes use only one parameter, so I’ll have to now take that into account and move eip forward only 2 spots for these instructions.

There’s also now the concept of parameter modes. If the instruction’s low two digists are the opcode, and the high up to three (implied 0 if less than 3) are flags. 0 means that the parameter references a location in the program, just as before. A 1 means that the parameter is an immediate value, and to use it.

For part two, I’m given four more opcodes - two conditional jumps and two comparisons. These are enough to allow me to change what the program does based on the input.

## Solution

### Part 1

The first thing I did was to turn my computer into a class. As the computer becomes more complex, this just gives me more flexibility to keep the program as a value in the class and call various functions.

In the __init__ function, I’ll save the program and the input value. I’ll have a compute function that is largely the function from day 2. And I’ll add a function get_param that takes a mode and a value and returns either the value or the value from that location in the program.

The logic for opcode 3 and 4 is quite simple to add. I’ll make some other small changes, like incrementing eip inside of the switch block instead of just advancing four for all instructions.

The biggest challenge is parsing the instruction to get the opcode and the modes. I’ll use mod to get the opcode, and then integer division to isolate the mode, and string formatting to produce a three-digit string that I can split into three modes. Even if all instructions don’t require three modes, it’s easier to just zero-pad and store three for all.

#!/usr/bin/env python3

import sys

class computer:
def __init__(self, program, input_):
self.program = program
self.input = input_

def get_param(self, mode, value):
if mode == "0":
return self.program[value]
else:
return value

def compute(self):
eip = 0
while True:
inst = self.program[eip]
op = inst % 100
mode3, mode2, mode1 = f"{inst // 100:03d}"
assert mode3 == "0"
if op == 1:
self.program[self.program[eip + 3]] = self.get_param(
mode1, self.program[eip + 1]
) + self.get_param(mode2, self.program[eip + 2])
eip += 4
elif op == 2:
self.program[self.program[eip + 3]] = self.get_param(
mode1, self.program[eip + 1]
) * self.get_param(mode2, self.program[eip + 2])
eip += 4
elif op == 3:
self.program[self.program[eip + 1]] = self.input
eip += 2
elif op == 4:
print(f"{self.program[self.program[eip+1]]}")
eip += 2
elif op == 99:
break
else:
print("Error")
sys.exit()

with open(sys.argv, "r") as f:

comp = computer(list(map(int, program_str.split(","))), 1)
print("Part 1:")
comp.compute()


When I run this, I get the result:

$time ./day5.py 05-puzzle_input.txt 1 Part 1: 3 0 0 0 0 0 0 0 0 9219874 real 0m0.021s user 0m0.016s sys 0m0.004s  As the prompt told me, it will print the result of each diagnostic, and then give a diagnostic code at the end. My solution is 9219874. ### Part 2 Part two is relatively straight forwrad. I just need to add these four additional op codes. The two jumps are simply comparing the first parameter to 0, and then setting or incrementing eip based on the result:  elif op == 5: if self.get_param(mode1, self.program[eip + 1]) != 0: eip = self.get_param(mode2, self.program[eip + 2]) else: eip += 3 elif op == 6: if self.get_param(mode1, self.program[eip + 1]) == 0: eip = self.get_param(mode2, self.program[eip + 2]) else: eip += 3  The two comparisons are just setting the third parameter to the result of the comparison of the first two:  elif op == 7: self.program[self.program[eip+3]] = int(self.get_param(mode1, self.program[eip + 1]) < self.get_param(mode2, self.program[eip + 2])) eip += 4 elif op == 8: self.program[self.program[eip+3]] = int(self.get_param(mode1, self.program[eip + 1]) == self.get_param(mode2, self.program[eip + 2])) eip += 4  Now I’ll add code at the bottom to create a new computer with input 5, and compute: $ time ./day5.py 05-puzzle_input.txt
Part 1:
3
0
0
0
0
0
0
0
0
9219874

Part 2:
5893654

real    0m0.027s
user    0m0.023s
sys     0m0.004s


## Final Code

#!/usr/bin/env python3

import sys

class computer:
def __init__(self, program, input_):
self.program = program
self.input = input_

def get_param(self, mode, value):
if mode == "0":
return self.program[value]
else:
return value

def compute(self):
eip = 0
while True:
inst = self.program[eip]
op = inst % 100
mode3, mode2, mode1 = f"{inst // 100:03d}"
assert mode3 == "0"
if op == 1:
self.program[self.program[eip + 3]] = self.get_param(
mode1, self.program[eip + 1]
) + self.get_param(mode2, self.program[eip + 2])
eip += 4
elif op == 2:
self.program[self.program[eip + 3]] = self.get_param(
mode1, self.program[eip + 1]
) * self.get_param(mode2, self.program[eip + 2])
eip += 4
elif op == 3:
self.program[self.program[eip + 1]] = self.input
eip += 2
elif op == 4:
print(f"{self.program[self.program[eip+1]]}")
eip += 2
elif op == 5:
if self.get_param(mode1, self.program[eip + 1]) != 0:
eip = self.get_param(mode2, self.program[eip + 2])
else:
eip += 3
elif op == 6:
if self.get_param(mode1, self.program[eip + 1]) == 0:
eip = self.get_param(mode2, self.program[eip + 2])
else:
eip += 3
elif op == 7:
self.program[self.program[eip + 3]] = int(
self.get_param(mode1, self.program[eip + 1])
< self.get_param(mode2, self.program[eip + 2])
)
eip += 4
elif op == 8:
self.program[self.program[eip + 3]] = int(
self.get_param(mode1, self.program[eip + 1])
== self.get_param(mode2, self.program[eip + 2])
)
eip += 4
elif op == 99:
break
else:
print("Error")
sys.exit()

with open(sys.argv, "r") as f: